Simple one. If the differential equation is like $\frac{\mathrm{d}x}{\mathrm{d}y} = Q(x)$, then solution would be $y=\int Q(x) \mathrm{d}x$.
Separation of variables. If the differential equation is like $\frac{\mathrm{d}x}{\mathrm{d}y} = f(x)g(y)$, then it could be re-write in $\frac{1}{f(x)}\mathrm{d}x = g(y) \mathrm{d}y$, then integrating each side and then the solution can be goten.
Integrating factor. If the differential equation is like $\frac{\mathrm{d}x}{\mathrm{d}y}+P(x)y=Q(x)y$, then it could become $$e^{\int P(x) \ \mathrm{d}x} \frac{\mathrm{d}x}{\mathrm{d}y} + e^{\int P(x) \ \mathrm{d}x} \ P(x)y = e^{\int P(x) \ \mathrm{d}x} \ Q(x) $$ by multiplying $$e^{\int P(x) \ \mathrm{d}x}$$, so that $$e^{\int P(x) \ \mathrm{d}x} \frac{\mathrm{d}x}{\mathrm{d}y} + e^{\int P(x) \ \mathrm{d}x} \ P(x)y = e^{\int P(x) \ \mathrm{d}x} \ Q(x) \ $$ using product rule, $$ \frac{\mathrm{d}}{\mathrm{d}x} (e^{\int P(x) \ \mathrm{d}x} y) = e^{\int P(x) \ \mathrm{d}x} Q(x) $$
Unlike discrets probability distribution, continuous probability distribution is continuous. The variables of the former can only be integers, while the latter is the entire field of real numbers.
Similar to discrete notation, the probability is usually written as $P(X \leq x)$. However, it should be noted that for a continuous probability distribution, $P(X=x)=0$, that is, for a continuous probability distribution, the probability of obtaining a particular value is 0. Notes: the reference to “probability 0” here DOES NOT mean that it is impossible (it can be analogous to “taking a random point on the field of real numbers, the probability that the point is rational is 0”).
$x$: random variable, where $x \in \mathbb{R} \quad or \quad x \in \mathbb{Z}$
$P(x=k)=a$: For the event $x=k$, his probability is $a$. Note that the probability of any event is greater than or equal to 0 and less than or equal to one.
for example, x: outcome of coin tossing. tail:0, head:1. $$P(x=0)=\frac{1}{2}, \quad P(x=1)=\frac{1}{2}$$
Notes: for a discrete probability distribution, the sum of the probabilities of all events must be 1, i.e: $$\sum_{i=-\infty}^{\infty} P(x=i) = 1$$
This is often used as a way of checking whether a probability distribution is valid.
Complex number: $a+bi$, where $a$ is real part,$bi$ is imaginary part. $a={\rm Re}(\mathbb{Z})$, $b={\rm Im}(\mathbb{Z})$
Notes: $i^2=-1$, $i^3=-i$, $i^4=1$
It can also be written in vector form, such as $a \choose b$ (Note: this writing is only useful when calculating addition and subtraction, other operations are more troublesome).